(meteorobs) Camera sky coverage math question

[James Beauchamp]

Very rough method...

350 nm = 640 km

A = Pi * (640,000)^2 = 1.268796 E^12 m^2  (1,286,796 km^2)

Earth Surface = 510.072 E^6 Km^2  (510,072,000 km^2)

Your sky = ~2.5 %, neglecting atmospherics, earth curvature, ect.

Again, very rough, but I bet it would be pretty close to a more advanced analysis.




--- On Mon, 4/4/11, Thomas Ashcraft <ashcraft at heliotown.com> wrote:

> From: Thomas Ashcraft <ashcraft at heliotown.com>
> Subject: (meteorobs) Camera sky coverage math question
> To: "Global Meteor Observing Forum" <meteorobs at meteorobs.org>
> Date: Monday, April 4, 2011, 9:41 AM
> I have a math question.
> 
> My all-sky camera can see fireballs in the sky for
> approximately 350 
> miles/ 563 km in all directions.  I am wondering what
> percentage of the 
> Earth's sky this camera can see?
> 
> Thanks for your math help in advance.
> 
> Thomas  /  New Mexico
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